Static Door Hinge Problem

In this example the elbow force happens to be vertical because the problem assumes the tension by the biceps to be vertical as well.

Static door hinge problem.

Forces on door hinges a swinging door that weighs w 400 0 n w 400 0 n is supported by hinges a and b so that the door can swing about a vertical axis passing through the hinges figure 12 16. Remove the top hinge pin and lay it on a concrete floor. And the known weight. Three forces act on the door slab.

I was also able to use a screw driver to open the jaws of the friction hinge a smidgen. 10 4 i have the friction hinge door so i am familiar with it and it s problems. One of the most common problems that might affect your door installation process is caused by the hinge plates being out of alignment. Mine i had to adjust the camber as i couldn t get it to latch withough slamming.

An unknown force. Using a hammer strike the pin in the middle this will cause a slight bend in the pin. This will keep the weight of the door from binding on the other hinges. Mark both sides of the door.

Start by closing the door. On the latch side a door is cut at a slight bevel to make it easier to close. The forces that the door exerts on its hinges can be found by simply reversing the directions of the forces that the hinges exert on the door. An unknown force.

Works good now rjsurfer. In the initial analysis of a problem hinge joints should always be assumed to exert a force in an arbitrary direction and then you must solve for all components of a hinge force independently. Simply tap the pin back into the hinge and test the door. Hence our task is to find the forces from the hinges on the door.

To solve this check that your door jamb is on the same plane so the door can close properly. If a door binds open it grasp the knob and lift up to see if a hinge is loose. If one is loose remove two or more screws and try driving in longer screws. The hinges are placed symmetrically at the door s edge.

The door has a width of b 1 00 m b 1 00 m and the door slab has a uniform mass density. The ideal is a 1 8 inch gap between the door and jamb at all points.